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Three persons A1, A2, A3 are to speak at a function along with 5 other persons. If the persons speak in random order, then what is the probability that A1 speaks before A2 and A2 before A3 ?

Three persons A1, A2, A3 are to speak at a function along with 5 other persons.
If the persons speak in random order, then what is the probability that A1 speaks before A2 and A2 before A3 ?
 

Grade:11

1 Answers

Vijay Mukati
askIITians Faculty 2590 Points
7 years ago
Dear Student,

For 8 speakers, total arrangement will be 8!. Now out of 8 postions selecting any three positions for (A,B and C in order) will be 8C3 are remaining can be arranged in 5! ways.

Therefore, Probability will be (8C3)*5!/8! = 1/6

Thanks.

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