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This is a question relatedc to permutations and combinations.


one year ago

Vedant
35 Points
							Dear Student, The correct answer is option B. Statement 1: We separate the youngest and the eldest boys and divide the remaining boys into groups of 2, 3, 3.This can be done in /$(\frac{\fact{8}}{\fact{2}\fact{2}\fact{3}\fact{3}})/$ ways. Now choose one of the groups having 3 members in 2 ways and put the eldest person in that group. The youngest boy goes in the group with 2 members. Thus the final answer turns out to be /$(\frac{\fact{8}}{\fact{2}\fact{3}\fact{3}})/$. Statement 2: Permute the (2m+n) objects and divide by m!, m! and n! as they are to be grouped. But this results in double counting as we can count either of the groups containing m elemnts first, thus we must divide by 2. So the answer is /$(\frac{\fact{2m+n}}{2\fact{m}^2\fact{n}})/$  Therefore both the statments are true but Statement 2 is not the correct explanation of Statement 1. Regards, Vedant

6 months ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions