there are n bags such that i’th bag contains i black and 2 white balls.Two balls are drawn from a randomly selected bag out of n bags.fInd the probability that both balls drawn are white. Answer =1/(n+2) i’m getting a different answer.

Question

Praveen Kumar Das · Answer

I here are n bags such that i’th bag contains i black and 2 white balls.Two balls are drawn from a randomly selected bag out of n bags.fInd the probability that both balls drawn are white GOT THE ANSWER 1/(N+2) NOW...Thanks

Ronak Singhvi · Answer

Assume that i have selected i’th bag probability of selecting 1 bag from n bags =1/n probability of selecting 2 white balls at a time from the selected bag = 2 C 2 / i+2 C 2 = 2/(i+2)(i+1) =[1/(i+1) – 1/(i+2) ]×2 toytal probability= 2/n ∑ (1/(i+1) – 1/(i+2) ] = 2/n [ ½ – 1/n+2] = 1/n+2

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there are n bags such that i’th bag contains i black and 2 white balls.Two balls are drawn from a randomly selected bag out of n bags.fInd the probability that both balls drawn are white. Answer =1/(n+2) i’m getting a different answer.

there are n bags such that i’th bag contains i black and 2 white balls.Two balls are drawn from a randomly selected bag out of n bags.fInd the probability that both balls drawn are white.

Answer =1/(n+2)

i’m getting a different answer.

2 Answers

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there are n bags such that i’th bag contains i black and 2 white balls.Two balls are drawn from a randomly selected bag out of n bags.fInd the probability that both balls drawn are white. Answer =1/(n+2) i’m getting a different answer.

there are n bags such that i’th bag contains i black and 2 white balls.Two balls are drawn from a randomly selected bag out of n bags.fInd the probability that both balls drawn are white. Answer =1/(n+2) i’m getting a different answer.

2 Answers

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there are n bags such that i’th bag contains i black and 2 white balls.Two balls are drawn from a randomly selected bag out of n bags.fInd the probability that both balls drawn are white.

Answer =1/(n+2)

i’m getting a different answer.