MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade:
        
The value of x satisfying the equation [3(1 - 1/2 + 1/4 .....Infinity)]^log x base 10 = [20(1 - 1/4 + 1/16 .....Infinity)]^log 10base x
2 months ago

Answers : (1)

Aditya Gupta
823 Points
							
note that log 10base x= 1/log x base 10
so let log x base 10=y
also 3(1 - 1/2 + 1/4 .....Infinity)= 3/(3/2)= 2
and 20(1 - 1/4 + 1/16 .....Infinity)= 20*4/5= 16
so 2^y=16^(1/y)
or 2^y=2^(4/y)
or y=4/y
y= +-2= log x base 10
so x= 10^2 and 10^-2
so x= 100 or 1/100
2 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details