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The radius of a circle having minimum area which touches the curve y=4-x^2 and the line y=|x| is


2 years ago

Arun
24742 Points
							Centre : (0, 4-r)Length of perpendicular from (0, 4-r) to line x-y = 0 is: r = |(0 -4 +r)/$\sqrt$2|r - 4 = + - $\sqrt$2 rOn solvingr = 4($\sqrt$2 -1) RegardsArun (AskIITians forum expert)

2 years ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions