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The pth term of an AP is = a+(p-1)d
where a is the first term of the AP and d is the common difference
as pth term is equal to q therefore q=a+(p-1)d .....1
similarly qth term is equal to p
p=a+(q-1)d .......2
solve the two equations to get the value of a and d. It will come
a=p+q-1
d=-1
now (p+q)th term is =a+(p+q-1)d
put the values of a and d
=(p+q-1)+(p+q-1)(-1)
=(p+q-1)-(p+q-1)
=0
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