The number of ways in which we can arrange the digits 1,2,3,4,5,6,7,8,9 such that the product of 5 digits at any of the 5 consecutive positions is divisible by 7 is?

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Vedant · Answer

There is only one way to do so which is putting 7 in the middle Regards Vedant

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The number of ways in which we can arrange the digits 1,2,3,4,5,6,7,8,9 such that the product of 5 digits at any of the 5 consecutive positions is divisible by 7 is?

The number of ways in which we can arrange the digits 1,2,3,4,5,6,7,8,9 such that the product of 5 digits at any of the 5 consecutive positions is divisible by 7 is?

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The number of ways in which we can arrange the digits 1,2,3,4,5,6,7,8,9 such that the product of 5 digits at any of the 5 consecutive positions is divisible by 7 is?

The number of ways in which we can arrange the digits 1,2,3,4,5,6,7,8,9 such that the product of 5 digits at any of the 5 consecutive positions is divisible by 7 is?

1 Answers

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Other Related Questions on Magical Mathematics[Interesting Approach]

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