The number of arrangements that can be formed from the letters a,b,c,d,e,f taken 3 at a time without repetition and each arrangement containing at least one vowel? OPTIONS: 96 128 24 72

Question

Arun · Answer

Dear student Required solution is (2C1 * 4C2 + 2C2 * 4C1) * 3! = (2 * 6 + 1 * 4) *6 = (16) *6 = 96 ways Regards Arun (askIITians forum expert)

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The number of arrangements that can be formed from the letters a,b,c,d,e,f taken 3 at a time without repetition and each arrangement containing at least one vowel? OPTIONS: 96 128 24 72

The number of arrangements that can be formed from the letters a,b,c,d,e,f taken 3 at a time without repetition and each arrangement containing at least one vowel?
OPTIONS:

96

128

24

72

The number of arrangements that can be formed from the letters a,b,c,d,e,f taken 3 at a time without repetition and each arrangement containing at least one vowel?

1 Answers

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The number of arrangements that can be formed from the letters a,b,c,d,e,f taken 3 at a time without repetition and each arrangement containing at least one vowel? OPTIONS: 96 128 24 72

The number of arrangements that can be formed from the letters a,b,c,d,e,f taken 3 at a time without repetition and each arrangement containing at least one vowel?OPTIONS: 96 128 24 72

The number of arrangements that can be formed from the letters a,b,c,d,e,f taken 3 at a time without repetition and each arrangement containing at least one vowel?

1 Answers

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Other Related Questions on Magical Mathematics[Interesting Approach]

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The number of arrangements that can be formed from the letters a,b,c,d,e,f taken 3 at a time without repetition and each arrangement containing at least one vowel?
OPTIONS:

96

128

24

72