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The AM of the series 1,3,9,27,81,..........,3n is:
please reply fast

ASh , 7 Years ago
Grade 12th Pass
anser 1 Answers
Arun
Dear Ashwin
 
As there are n+1 terms
Hence A.M = 3^0 + 3¹ + 3² + 3³ +.......+3n /(n+1)
= 1 (3n+1 -1) /2(n+1)

Regards
Arun (askIITians forum expert)
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Last Activity: 7 Years ago
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