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The AM of the series 1,3,9,27,81,..........,3 n is: please reply fast

The AM of the series 1,3,9,27,81,..........,3n is:
please reply fast

Grade:12th Pass

1 Answers

Arun
25758 Points
4 years ago
Dear Ashwin
 
As there are n+1 terms
Hence A.M = 3^0 + 3¹ + 3² + 3³ +.......+3n /(n+1)
= 1 (3n+1 -1) /2(n+1)

Regards
Arun (askIITians forum expert)

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