Flag Magical Mathematics[Interesting Approach]> [sqrt(1)]+[sqrt(2)]+[sqrt(3)]+.......+[sq...
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[sqrt(1)]+[sqrt(2)]+[sqrt(3)]+.......+[sqrt(2115)]=?

Matt Farrel , 10 Years ago
Grade 10
anser 1 Answers
Arun Kumar

Last Activity: 10 Years ago

Hello Student,

\\\left \lfloor \sqrt1 \right \rfloor=1 \\\left \lfloor \sqrt2 \right \rfloor=1 \\=>n=1=>1,2,3=>(2^2-1^2) \\=>n=2=>4,5,6,7,8=>(3^2-2^2) \\\sqrt{2014}=44 \\=>\sum_{1}^{43}((r+1)^2-r^2)=\sum_{1}^{43}(2r+1)=n(n+1)+n=43*44+44 \\$after 44 starts $add=44*(2014-1936+1)
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
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