# solve for x3x+31-x-4please solve it with explanationthanks in advance for solution

Arun
25758 Points
4 years ago
Dear student

We can write it as

3^x + 3/3^x  - 4 = 0

Now assume 3^x = t

t + 3/t  - 4 = 0

t² -4t +3 = 0

(t-1) ( t-3) = 0

t = 1 and t = 3

Hence

3^x = 1
x = 0

&

3^x = 3

x = 1

Regards
Arun
Om
111 Points
4 years ago
3x+31-x-4 =0
we can write the above equaion as
3x+(31/3x)-4=0
Let 3be y
y+(3/y)-4=0
y2+3-4y=0   ( by taking LCM)
(y-1)(y-3)=0  (by factorization)
y =  3  or 1
3x= 31  or  30   (as 30=1)
So x= 1or 0

Om
111 Points
4 years ago
I forgot to mention the formulas
These are the formulas that i used to solve your question
am/an=am-n         (this is the formula that i usen in 3rd line)

using this we can solve above equation in the question