Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Solve 3x+8>2, when (i) x is an integer (ii) x is a real number

Solve 3x+8>2, when

(i) x is an integer

(ii) x is a real number

Grade:12th pass

1 Answers

Harshit Singh
askIITians Faculty 5963 Points
9 months ago
Welcome to AskIITians

Given Linear inequality: 3x+8>2

The given inequality can also be written as:

3x+8 -8 > 2 -8 …(1)

In the above inequality, -8 is multiplied on both the sides, as it does not change the definition of the given expression.

Now, simplify the expression (1)

⇒ 3x > -6

Now, both the sides, divide it by 3

⇒ 3x/3 > -6/3

⇒ x > -2

(i) x is an integer

Hence, the integers greater than -2 are -1,0,1,2,…etc

Thus, when x is an integer, the solutions of the given inequality are -1,0,1,2,…

Hence, the solution set for the given linear inequality is {-1,0,1,2,…}

(ii) x is a real number

If x is a real number, the solutions of the given inequality are all the real numbers, which

are greater than 2.

Therefore, in the case of x is a real number, the solution set is (-2, ∞)

Thanks

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free