Prove that (1+w)^3 - (1+w^2)^3=0 Here W is cube root of unity Please provide the whole proof 😊😊.

Question

Arun · Answer

Dear Piyush As we know 1 + w + w 2 = 0 hence we can write 1 + w = – w 2 and 1 + w 2 = –w and w 3 = 1 when required Now (1 + w) 3 – (1 + w 2 ) 3 ( – w 2 ) 3 – ( –w) 3 – w 6 + w 3 – 1 + 1 = 0 = RHS Hence Proved Regards Arun (askIITians forum expert)

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Prove that (1+w)^3 - (1+w^2)^3=0 Here W is cube root of unity Please provide the whole proof 😊😊.

Prove that (1+w)^3 - (1+w^2)^3=0 Here W is cube root of unity Please provide the whole proof 😊😊.

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Prove that (1+w)^3 - (1+w^2)^3=0 Here W is cube root of unity Please provide the whole proof 😊😊.

Prove that (1+w)^3 - (1+w^2)^3=0 Here W is cube root of unity Please provide the whole proof 😊😊.

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