Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

probability of hitting a target by Ais7/10and by B is 4/10 both are independent events.find probability of hitting the target by B ,target is already hit?

probability of hitting a target by Ais7/10and by B is 4/10 both are independent events.find probability of hitting the target by B ,target is already hit?

Grade:12

2 Answers

Arun
25763 Points
2 years ago
Dear student 
 
target hitting probability =  7/10 * 6/10 + 3/10 * 4/10 + 7/10 * 4/10 = 82/100
 
now probability oh hitting target B given target has been hit already = 40/ 100 / 82/100 = 40/82
 
= 20/41
Chandrasekhar Sarma
26 Points
24 days ago
Probability that A hits the target = P(A) = 7/10.
Probability that B hits the target = P(B) = 4/10
Probability that target is hit = P(A+B) = P(A) + P(B)- P(AB)=P(A)+P(B)-P(A).P(B)=7/10+4/10-7/10*4/10=82/100
P((B/(A+B)) =P(B.(A+B))/P(A+B)= P(B)/P(A+B)=(4/10)/(82/100)=20/41.
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free