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Plz evaluate question 8 in an easy way. Check attachmemt.

nadeemafzal111 , 6 Years ago
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anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear student
see in second term
it is a +b+ c = 0
then a^3 + b^3 + c^3 =3abc
and in FIRST term
everyterm in denominator is 3 times of Numerator.
hence it is 1/27 – 1/27 = 0

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