Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Plz answer the above mentioned question in photo attached,plz fast,

Plz answer the above mentioned question in photo attached,plz fast,

Question Image
Grade:11

1 Answers

Shashank Singh
askIITians Faculty 57 Points
3 years ago
let G1 be the first term of the GP
G2 be the second term of GP
G3 be the third term of the GP
G1= n(n+1)/2
G2= sqrt10/3 (n(n+1)(2n+1))/6
G3= (n(n+1))^2/ 4
G2/G1= common ratio= r= sqrt10/9 (2n+1).......... (1)
G3/G1= r^2= n(n+1)/2........ (2)
squaring (1) and comparing with (2), we get
10/81 (4n^2+4n+1)= (n^2+n)/2
n^2+n= 20
by solving this quadratic equation we get n=4........... [Ans]

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free