MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        
Pls anyone solve this.Fast i need answer im unable to solve it
11 months ago

Answers : (1)

Shashank Singh
askIITians Faculty
57 Points
							let the sides of an equilateral triangle be ‘a’
now using using geometry
we get the radius of circumcircle = R=a/v3
and radius of incircle = r= a/2v3
area of cicumcircle = pi*a^2/3
area of incircle = pi*a^2/12
the required probability = (area of circumcircle – area of incircle)/area of circumcircle
P(E)= (pi*a^2/3-pi*a^2/12)/pi*a^2/3
on solving we get P(E)=3/4= lambda1/lambda2
so, lambda1+lambda2= 7.......... [ans]
11 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 1,590 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details