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Grade: 12th pass
        
Please provide the complete solution of question in the attachment............ ... Ans is coming 2/9..... 
11 months ago

Answers : (1)

Arun
22956 Points
							
w^1 + w^2 + w^3 = 0 
w^1 = w^4 
w^2 = w^5 
1 = w^3 = w^6 

Probability that r1 = 1 or 4, r2 = 2 or 5, r3 = 3 or 6 
= 2/6 * 2/6 * 2/6 
= 1/27 
If the values of r1, r2, r3 are reshuffled, then also we will get w^r1 + w^r2 + w^r3 = 0 
The values of r1, r2, r3 can be reshuffled in 3! = 6 wats 
Therefore, the required probability = 6 * 1/27 = 2/9 
Ans: 2/9 
11 months ago
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