No of ordered triplets of natural number (x,y,z) for which xyz is less than and equal to 11
Tribhuvan , 8 Years ago
Grade 12
Magical Mathematics[Interesting Approach]> No of ordered triplets of natural number ...
1 AnswersSatdhruti Paul
Last Activity: 7 Years ago
You do this in 11 steps.
xyz = 11, this can then be done using the Permutation Combination technique of factoring
xyz = 10, a number into n factors. If a number is of the form N = 2a3b5c.... so on,i.e
xyz = 9, prime factorise it, then the number of possibilities of xyz = N is given by
. the answer isa+2c2 * b+2c2 * c+2C2. After finding all of the 11 answers, add them to get your final answer. Hope this helped!
.
.
.
.
and so on till
xyz = 2,
xyz = 1. → Here there’s only one solution x = y = z = 1
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