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Grade: 12
        No of ordered triplets of natural number (x,y,z) for which xyz is less than and equal to 11
one year ago

Answers : (1)

Satdhruti Paul
19 Points
							
You do this in 11 steps.
xyz = 11, this can then be done using the Permutation Combination technique of factoring
xyz = 10, a number into n factors. If a number is of the form N = 2a3b5c.... so on,i.e
xyz = 9,  prime factorise it, then the number of possibilities of xyz = N is given by
.            the answer isa+2c2 * b+2c2 * c+2C2. After finding all of the 11 answers, add them to get your final answer. Hope this helped!
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and so on till
xyz = 2,
xyz = 1. → Here there’s only one solution x = y = z = 1
one year ago
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