∑ nCr * (n-r) * cos{(2*r*pi)/n} where ‘r’ ranges from ‘0’ to ‘n’ = ??
∑ nCr * (n-r) * cos{(2*r*pi)/n}
where ‘r’ ranges from ‘0’ to ‘n’ = ??
Last Activity: 2 Years ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago