Guest

∑ nCr * (n-r) * cos{(2*r*pi)/n} where ‘r’ ranges from ‘0’ to ‘n’ = ??

∑ nCr * (n-r) * cos{(2*r*pi)/n} 
 where ‘r’ ranges from ‘0’ to ‘n’ = ??

Grade:12

1 Answers

Sourabh Singh IIT Patna
askIITians Faculty 2104 Points
7 years ago
Hiii

Use cos in terms of Exponential adn then separate out the terms. Then operate individually you will get the answer.


Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free