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∑ nCr * (n-r) * cos{(2*r*pi)/n} where ‘r’ ranges from ‘0’ to ‘n’ = ??

∑ nCr * (n-r) * cos{(2*r*pi)/n} 
 where ‘r’ ranges from ‘0’ to ‘n’ = ??

Grade:12

1 Answers

Sourabh Singh IIT Patna
askIITians Faculty 2104 Points
6 years ago
Hiii

Use cos in terms of Exponential adn then separate out the terms. Then operate individually you will get the answer.


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