Let f(x)=|x-2| where x is a real number.Which one of the following is true?
OPTIONS:
f is periodic
f(x+y)=f(x)+f(y)
f is an odd function
f is not a 1-1 function

Question

Let f(x)=|x-2| where x is a real number.Which one of the following is true? OPTIONS: f is periodic f(x+y)=f(x)+f(y) f is an odd function f is not a 1-1 function

Anish Singhal · Answer

f is not one one, refer graph of modulus functions which are always V shape curve hence not one one

Deepak Kumar Shringi · Answer

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Let f(x)=|x-2| where x is a real number.Which one of the following is true? OPTIONS: f is periodic f(x+y)=f(x)+f(y) f is an odd function f is not a 1-1 function

Let f(x)=|x-2| where x is a real number.Which one of the following is true?
OPTIONS:
f is periodic
f(x+y)=f(x)+f(y)
f is an odd function
f is not a 1-1 function

Let f(x)=|x-2| where x is a real number.Which one of the following is true?
OPTIONS:
f is periodic
f(x+y)=f(x)+f(y)
f is an odd function
f is not a 1-1 function

2 Answers

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Let f(x)=|x-2| where x is a real number.Which one of the following is true? OPTIONS: f is periodic f(x+y)=f(x)+f(y) f is an odd function f is not a 1-1 function

Let f(x)=|x-2| where x is a real number.Which one of the following is true?OPTIONS:f is periodicf(x+y)=f(x)+f(y)f is an odd functionf is not a 1-1 function

Let f(x)=|x-2| where x is a real number.Which one of the following is true?OPTIONS:f is periodicf(x+y)=f(x)+f(y)f is an odd functionf is not a 1-1 function

2 Answers

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Other Related Questions on Magical Mathematics[Interesting Approach]

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Let f(x)=|x-2| where x is a real number.Which one of the following is true?
OPTIONS:
f is periodic
f(x+y)=f(x)+f(y)
f is an odd function
f is not a 1-1 function

Let f(x)=|x-2| where x is a real number.Which one of the following is true?
OPTIONS:
f is periodic
f(x+y)=f(x)+f(y)
f is an odd function
f is not a 1-1 function