In throwing of a pair of dice find the probability of the event total is not eat and not 11
In throwing of a pair of dice find the probability of the event total is not eat and not 11
Manish patel , 6 Years ago
Grade 12
Magical Mathematics[Interesting Approach]> In throwing of a pair of dice find the pr...
1 AnswersArun
Last Activity: 6 Years ago
Dear Manish
sum is 8 = (6,2)(2,6)(5,3)(3,5)(4,4)
hence probability of getting 8 = 5 / 36
sum is 11 = (6,5)(5,6)
hence probability of getting 11 = 2 / 36
now
P (A U B) = 5 + 2 / 36 = 7 / 36
Hence nether 8 come nor 11, probability = P (A U B) ‘ = 1 – 7 / 36 = 29 / 36
Regards
Arun (askIITians forum expert)
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