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In throwing of a pair of dice find the probability of the event total is not eat and not 11

Manish patel , 7 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear Manish
 
sum is 8 = (6,2)(2,6)(5,3)(3,5)(4,4)
hence probability of getting 8 = 5 / 36
sum is 11 = (6,5)(5,6)
hence probability of getting 11 = 2 / 36
now 
P (A U B) = 5 + 2 / 36 = 7 / 36
Hence nether 8 come nor 11, probability = P (A U B) ‘ =  1 –  7 / 36 = 29 / 36
 
Regards
Arun (askIITians forum expert)

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