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P^2-Q^2 can be written as (P+Q)(P-Q). P+Q is equal to (x+a)^n and P-Q is equal to nC0×x^n-nC1×x^(n-1)+nC2×x^(n-2)-… or (x-a)^n.
So P^2-Q^2=(x+a)^n×(x-a)^n=(x^2-a^2)^n
(I) part is proved
similarily if we subtract (p –q)^2 from (p+q)^2
we get 4pq which will directly come to (x+a)^2n – (x –a)^2n
(II) part is proved
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