Arun
Last Activity: 7 Years ago
Sorry, I got your question
xy = a …....(i)
xz = b …....(ii)
yz = c …......(iii)
now multiply (i) and (ii)
x2yz = ab
similarly
xy2z = ac
xyz2 = bc
now x2 = ab/yz = ab/c
similarly
y2 = ac / xz = ac/b
z2 = bc/ xy = bc / a
hence
x2 + y2 + z2 = ab/c + ac/b + bc/a
Regards
Arun (askIITians forum expert)