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Use the formula tn= a+(n-1)d =n2+n+1(sorry n2= n square) . To get square term here lets assume d=n . So a+n2-n=n2+n+1. So we can solve for a and it comes up to be 2n+1.
So by using a=2n+1 and d=n we can get nth term as n2+n+1. This is not the only assumed values,there may be much more . So how could you say that it is not possible??
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