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If the sum n.1+(n-1)+(n-2).3+.........+2.(n-1)+1.n is equal toA 1/6n(n+1)1B 1/6n²(n+1)C 1/6n(n+1)(n+2)1/6n(n+1)(2n+1)
Dear student the r th term will be r(n-r+1) it is summation of r(n-r+1) where r varies from 1 to n; SUM ( (n+1)r - r^2 ) = (n+1)(n)(n+1)/2 - (n)(n+1)(2n+1)/6
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