If half of the total surface area of a cuboid is equal to the square of its diagonal then prove that the cuboid is actually a cube.

Question

Arun · Answer

Dear student Total surface area = 2 (lb+ bh+ hl) Length of diagonal = √(l²+b²+h²) Hence 2(lb +bh+ hl) = l² +b²+h² Now so it will be l = b = h Hence it will be a cube

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If half of the total surface area of a cuboid is equal to the square of its diagonal then prove that the cuboid is actually a cube.

If half of the total surface area of a cuboid is equal to the square of its diagonal then prove that the cuboid is actually a cube.

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If half of the total surface area of a cuboid is equal to the square of its diagonal then prove that the cuboid is actually a cube.

If half of the total surface area of a cuboid is equal to the square of its diagonal then prove that the cuboid is actually a cube.

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Magical Mathematics[Interesting Approach]

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

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