- If
- a^x=b
- b^y=c
- c^z=a
- Prove xyz=1
- Please give the solution
- If
- a^x=b
- b^y=c
- c^z=a
- Prove xyz=1
- Please give the solution
Shrey , 11 Years ago
Grade 11
Magical Mathematics[Interesting Approach]> If a^x=b b^y=c c^z=a Prove xyz=1 Please g...
6 Answers
Rinkoo Gupta
ax=b => x=logab
by=c=> y=logbc
cz=a=> z=logca
xyz=(logab.logbc).logca
=logac.logca
=logaa
=1
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
Approved Last Activity: 11 Years ago
Sher Mohammad
a^xyz
=(a^x)^yz
=b^yz
=(b^y)^z
=c^z
=a
by comparision xyz=1 proved
Sher Mohammad
faculty askiitians
Approved Last Activity: 11 Years ago
pramod Gopinath
a^x=b
b^y=c =>a^xy=c
c^z=a =>a^xyz=a =>xyz=1
Swati Kohli
In equation:
a^x=b (put value of a i.e. c^z)
=> c^z(x)=b
Now, put value for c i.e. b^y
=> b^y(zx)=b
=> b^(xyz)=b^1
Therefore, xyz=1 (Taking base as same)
SHANMUKESHWAR
c^z=aa^x=b,
b^y=c(c^z)^x=b (b^y)^zx=b
b^xyz=b^1 so
xyz=1
Sani Chattopadhyay
If a = b = c = 1 then what will you tell??????? You must think about this....This was a CAT question....So it can not be so trivial..
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