How many of the non-negative integers from 0 to 9999 have no two adjacent digits the same how to approch this ?

Question

Saurabh Koranglekar · Answer

Dear student

Using permutations and combinations approach

1 digits -> 10 numbers
2 digits -> 9*9 = 81 numbers
3 digits -> 9*9*8= 648 numbers
4 digits ->9*9*8*7= 4536 numbers

Total = 5275 numbers

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How many of the non-negative integers from 0 to 9999 have no two adjacent digits the same how to approch this ?

How many of the non-negative integers from 0 to 9999 have no two adjacent digits the same

how to approch this ?

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How many of the non-negative integers from 0 to 9999 have no two adjacent digits the same how to approch this ?

How many of the non-negative integers from 0 to 9999 have no two adjacent digits the same how to approch this ?

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How many of the non-negative integers from 0 to 9999 have no two adjacent digits the same

how to approch this ?