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How many integers between 10000 and 99999 (5 digits), contain only the digits 2,3,4,6 and 8, and no digit appears twice?

Mayank , 4 Years ago
Grade 12th pass
anser 2 Answers
Saurabh Koranglekar

Last Activity: 4 Years ago

Dear student

The number is exclusively formed by 2,3,4,6,8 ie 5 digits no twice appearance

number of ways of arranging is 5!

so total number is 120

Regards

Arun

Last Activity: 4 Years ago

Dear student
 
For no repetition, there will be 5! = 120 numbera.
 
Hope it helps
 
Thanks and regards
Arun

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