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For finding least no of five digits which is exactly divisible by 41, why do we subtract the remainder from the divisor and then add it to the dividend to get the answer...can't it be done by directly adding the remainder to the dividend??

For finding least no of five digits which is exactly divisible by 41, why do we subtract the remainder from the divisor and then add it to the dividend to get the answer...can't it be done by directly adding the remainder to the dividend??

Grade:12th pass

1 Answers

Sourabh Singh IIT Patna
askIITians Faculty 2104 Points
4 years ago
Hii

You just have to find the number which is of 5 digits and a multiple of given number 41 . Rest everything can be avoided completely

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