# Find the value of k if the straight line 6x-10y+3=0,kx-5y+8=0 are parallel

Debarati
105 Points
one year ago
Parallel lines means that this system of equation has no solution.
So, a1/a2=b1/b2$\neq$c1/c2
=> 6/k=-10/-5$\neq$3/8
=> 6/k= 2
=> k= 3
$\therefore$k= 3

I hope you understood.