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Find the 100th place digit of a number forming from digits 1 to 9 without repeatition and number passes the divisibility test of 11 means difference of sum of alternative digits is 0 or divisible by 11.

Ronit Dutta , 7 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear Ronit
 
The 100th place digit would be 4.
As the largest no. which is divisible by 11 having digits 1 to 9 is 978653412 ,
the difference of the sum of the digits at even place and odd place is 11, which is a multiple of 11.
 
Regards
Arun (askIITians forum expert)

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