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Grade: 12th pass
        
Find the 100th place digit of a number forming from digits 1 to 9 without repeatition and number passes the divisibility test of 11 means difference of sum of alternative digits is 0 or divisible by 11.
2 years ago

Answers : (1)

Arun
23751 Points
							
Dear Ronit
 
The 100th place digit would be 4.
As the largest no. which is divisible by 11 having digits 1 to 9 is 978653412 ,
the difference of the sum of the digits at even place and odd place is 11, which is a multiple of 11.
 
Regards
Arun (askIITians forum expert)
2 years ago
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