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Can any please help me solve the sums 1, 2, 3. I will give you likes if you do that. I need it urgently.

SR Roy , 6 Years ago
Grade 10
anser 1 Answers
Kalpit

Last Activity: 6 Years ago

Answer to 3rd : 
Let AD perpendicular BC. Therefore  H lies on AD. 
Angle (ADB)=90 therefore Angle(BAD)=90-B 
AS O IS CIRCUMCENTER 
AO =CO 
Angle(AOC)=2B as O is center of circumcircle 
Therefore Angle (OAC)=(180-2B)/2 = 90-B =Angle(BAD)

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