“A particle has an initial velocity of 100 m/s up to the right at 30° with the horizontal. The components of the acceleration are constant at ax=-4m/s^2 and ay=-20m/s^2. Computing the horizontal distance covered until the particle reaches a point 60m below its original elevation would be”

In this problem, the given is ay = -20ft/s^2

ay=-20m/s^2
Sy=voyt+1/2ayt^2
-60=50t-1/2(20) t^2
t = 6s

why did he substitute positive 20 instead of negative 20?

Question

“A particle has an initial velocity of 100 m/s up to the right at 30° with the horizontal. The components of the acceleration are constant at ax=-4m/s^2 and ay=-20m/s^2. Computing the horizontal distance covered until the particle reaches a point 60m below its original elevation would be”

In this problem, the given is ay = -20ft/s^2

ay=-20m/s^2

Sy=voyt+1/2ayt^2

-60=50t-1/2(20) t^2

t = 6s

why did he substitute positive 20 instead of negative 20?

Mayank Ranka · Answer

There&rsquo;s sign change in that term because of ay

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