badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A man starts from the point P(-3,4) and reaches point Q(0,1) touching x axis at R such that PR+RQ is minimum, then point R is : ???

4 years ago

Answers : (2)

Leela Lochan
42 Points
							Assume the point to be (x,0).Using distance formulae calculate the distance.Then we get.           PR=[(x+3)^2+4^2]^1/2 and RQ=[x^2+1]^1/2 .Now add PR and RQ .let RQ+PR=Y.now differentiate the eq and equate it to zero.and solve for x.           Ans is (-4,0)
						
4 years ago
Gosula Madhukar
84 Points
							
It can be any point,because for any point on x-axis the sum of the distance is same as that of PQ.
i hope u are satisfied.
plese post if u r any further doubts.
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details