A frog is at the bottom of a 78 meter well. Each day he leaps 4 meters up the well. At night, while he is asleep, he slips 2 meters backwards.
How many days does it take him to escape from the well?

Question

A frog is at the bottom of a 78 meter well. Each day he leaps 4 meters up the well. At night, while he is asleep, he slips 2 meters backwards. How many days does it take him to escape from the well?

grenade · Answer

so you are asking for the days then lets take the problem wit let x days + x nights +4 meters leap=78 x days + x nights =x(2) on substituting the values we will get the answer as x+1 which will equals 38 plz aprve

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A frog is at the bottom of a 78 meter well. Each day he leaps 4 meters up the well. At night, while he is asleep, he slips 2 meters backwards. How many days does it take him to escape from the well?

A frog is at the bottom of a 78 meter well. Each day he leaps 4 meters up the well. At night, while he is asleep, he slips 2 meters backwards.
How many days does it take him to escape from the well?

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A frog is at the bottom of a 78 meter well. Each day he leaps 4 meters up the well. At night, while he is asleep, he slips 2 meters backwards. How many days does it take him to escape from the well?

A frog is at the bottom of a 78 meter well. Each day he leaps 4 meters up the well. At night, while he is asleep, he slips 2 meters backwards.How many days does it take him to escape from the well?

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Magical Mathematics[Interesting Approach]

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A frog is at the bottom of a 78 meter well. Each day he leaps 4 meters up the well. At night, while he is asleep, he slips 2 meters backwards.
How many days does it take him to escape from the well?