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A constable follow a thief who is 200m ahead of him. If the constable and the thief runs at speeds of 8km/hr and 7km/hr respectively,how soon would the constable catch the thief?
Let c=constable, t =theifVeocity:v(c)= 8km/hr=8*5/18 m/sec=40/18 m/secSimilarly, v(t)=35/18 m/secAs the velocity is uniform, we can use the formula,dist=v.tLet constable overtakes the theif at a dist. d from the theif, so the time taken to meet at that point will be same for both of them.i.e. t(c)=t (t)Therefore, (200+d)/v (c)=d/v(t) ( time= dist/v and constable has to cover 200m more than theif)(200 + d) * 18/40 = d *18/ 35 by putting the values of velocities and solving we get d=1400 m
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