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A,B,C,D are four points on a circle with radius R such that AC is perpendicular to BD and meets BD at E. prove that:EA 2 +EB 2 +EC 2 +ED 2 =4R 2

A,B,C,D are four points on a circle with radius R such that AC  is perpendicular  to BD and meets BD at E. prove that:EA2+EB2+EC2+ED2=4R2

Grade:10

1 Answers

pavaneswari
35 Points
6 years ago
you say A,B,C,D are 4 points on cirrcle with radius R and AC perpendicular to BD from these we say AC and BD are meets at center of the circle.so EA=EB=EC=ED=R that's mean EA2+EB2+EC2+ED2=4R2
 

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