A=(a^2 ab ac Ab b^2 BC Ac BC c^2) then a^2+b^2+c^2=1 then A^2=?

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Vikas TU · Answer

A 2 = a 4 +a 2 b 2 +a 2 c 2 +a 3 b+ab 3 +abc 2 +a 3 c+ab 2 c+ac 3 +a 3 b+ab 3 +abc 2 +a 2 b 2 +b 4 +b 2 c 2 +a 2 bc+b 3 c+a 3 c+ab 2 c+ac 3 +a 2 bc+b 3 c+bc 3 +a 2 c 2 +b 2 c 2 +c 4 =a 2 (a 2 +b 2 +c 2 )+a 3 b+ab 3 +abc 2 +a 3 c+ab 2 c+ac 3 +a 3 b+ab 3 +abc 2 +b 2 (a 2 +b 2 +c 2 )+a 2 bc+b 3 c+a 3 c+ab 2 c+ac 3 +a 2 bc+b 3 c+bc 3 +c 2 (a 2 +b 2 +c 2 ) We know that a 2 +b 2 +c 2 =1 from the identitiy. =a 2 +a 3 b+ab 3 +abc 2 +a 3 c+ab 2 c+ac 3 +a 3 b+ab 3 +abc 2 +b 2 +a 2 bc+b 3 c+a 3 c+ab 2 c+ac 3 +a 2 bc+b 3 c+bc 3 +c 2 =1+a 3 b+ab 3 +abc 2 +a 3 c+ab 2 c+ac 3 +a 3 b+ab 3 +abc 2 +a 2 bc+b 3 c+a 3 c+ab 2 c+ac 3 +a 2 bc+b 3 c+bc 3

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A=(a^2 ab ac Ab b^2 BC Ac BC c^2) then a^2+b^2+c^2=1 then A^2=?

A=(a^2 ab ac Ab b^2 BC Ac BC c^2) then a^2+b^2+c^2=1 then A^2=?

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A=(a^2 ab ac Ab b^2 BC Ac BC c^2) then a^2+b^2+c^2=1 then A^2=?

A=(a^2 ab ac Ab b^2 BC Ac BC c^2) then a^2+b^2+c^2=1 then A^2=?

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Other Related Questions on Magical Mathematics[Interesting Approach]

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