A(1,1),B(4,-2),C(5,5) are the vertices of triangle. The equation of the line through C parallel to the interior bisector of A is y=5 .how? explain

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Deepak Kumar Shringi · Answer

write the equation of line AB and AC now there will be two bisectors of AB and AC in which only one will pass from 5,5 and that will be answer
to write angle bisector refer to-
https://www.askiitians.com/iit-jee-straight-line/angle-bisectors/

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A(1,1),B(4,-2),C(5,5) are the vertices of triangle. The equation of the line through C parallel to the interior bisector of A is y=5 .how? explain

A(1,1),B(4,-2),C(5,5) are the vertices of triangle. The equation of the line through C parallel to the interior bisector of A is y=5 .how? explain

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A(1,1),B(4,-2),C(5,5) are the vertices of triangle. The equation of the line through C parallel to the interior bisector of A is y=5 .how? explain

A(1,1),B(4,-2),C(5,5) are the vertices of triangle. The equation of the line through C parallel to the interior bisector of A is y=5 .how? explain

1 Answers

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