60% of employees of XYZ Corporation are college graduates of this 10% in sales of the employees who did not graduate from college ,80% are in sales.What is the probability that-(i)an employee selected at random is in sales (ii)an employee selected at random is neither in sales nor a college graduate

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Adarsh Agiwal · Answer

let A be the event : the employees are graduate let B be the event : the employees are in sals. Given information : P(A) = 0.60 P(B/A) = 0.10 P(B/A)’ = 0.80 (i) P(B) = P(A int B) U (A’ int B) = P(A)* P(B/A) + P(A’). P(B/A)’ = 0.60*0.10 + 0.40*0.80 = 0.38 (ii) P(B int A’) = P(A U B)’ = 1 – P(A U B) = 1 – { P(A) + P(B) – P(A int B)} = 1 – { P(A) + P(B) – P(A)* P(B/A)} = 1 – {0.60 + 0.38 – 0.60 * 0.10} = 6.02 (approx)

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60% of employees of XYZ Corporation are college graduates of this 10% in sales of the employees who did not graduate from college ,80% are in sales.What is the probability that-(i)an employee selected at random is in sales (ii)an employee selected at random is neither in sales nor a college graduate

60% of employees of XYZ Corporation are college graduates of this 10% in sales of the employees who did not graduate from college ,80% are in sales.What is the probability that-(i)an employee selected at random is in sales (ii)an employee selected at random is neither in sales nor a college graduate

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