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60% of employees of XYZ Corporation are college graduates of this 10% in sales of the employees who did not graduate from college ,80% are in sales.What is the probability that-(i)an employee selected at random is in sales (ii)an employee selected at random is neither in sales nor a college graduate

60% of employees of XYZ Corporation are college graduates of this 10% in sales of the employees who did not graduate from college ,80% are in sales.What is the probability that-(i)an employee selected at random is in sales (ii)an employee selected at random is neither in sales nor a college graduate

Grade:12th pass

2 Answers

Adarsh Agiwal
13 Points
2 years ago
let A be the event : the employees are graduate
let B be the event : the employees are in sals.
 
Given information : 
P(A) = 0.60
P(B/A) = 0.10 
P(B/A)’ = 0.80
 
(i) P(B) = P(A int B) U (A’ int B)
           = P(A)* P(B/A) + P(A’). P(B/A)’
           = 0.60*0.10 + 0.40*0.80 
           = 0.38
 
(ii) P(B int A’) = P(A U B)’
                      = 1 – P(A U B)
                      = 1 – { P(A) + P(B) – P(A int B)}
                      = 1 – { P(A) + P(B) – P(A)* P(B/A)}
                      = 1 – {0.60 + 0.38 – 0.60 * 0.10}
                      = 6.02 (approx)
Sanskar Singh
13 Points
11 months ago
There is a calculation mistake in the 2nd part of the question....The answer of the 2nd part will be 0.08.
 

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