MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 10
        41 power^  77 divided    by  seven  the remainder is ? Ans 6
3 years ago

Answers : (2)

Rajat Pathak
40 Points
							
we can attempt it by using binomial theorem.  see how!!!
41=7*6+1
41^77=(7*6+1)^77
(7*6+1)^77=[77C0(7*6)^77]-[77C1(7*6)^76]+[77C2(7*6)^75]-.............+[77C76(7*6)]-[77C77*1]
HERE EVERY TERM IS DIVISIBLE EXCEPT THE LAST TERM WHICH IS -1.
THEREFORE THE REMAINDER IS-1.
WHICH CAN BE SAID AS 7-1=6
SO REMAINDER IS GONNA BE 6!!!
 
3 years ago
Rajat Pathak
40 Points
							
we can attempt it by using binomial theorem.  see how!!!
41=7*6+1
41^77=(7*6+1)^77
(7*6+1)^77=[77C0(7*6)^77]-[77C1(7*6)^76]+[77C2(7*6)^75]-.............+[77C76(7*6)]-[77C77*1]
HERE EVERY TERM IS DIVISIBLE EXCEPT THE LAST TERM WHICH IS -1.
THEREFORE THE REMAINDER IS-1.
WHICH CAN BE SAID AS 7-1=6
SO REMAINDER IS GONNA BE 6!!!!
 
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details