x6 - 10x3 + 27:

x6 - 10x3 + 27:


1 Answers

Badiuddin askIITians.ismu Expert
148 Points
12 years ago

Dear ajinkya

x6 - 10x3 + 27=0


let x3 =t

so t2 -10t +27 =0

discrimnent of this equation is negative so  no real value of t

so this equation has no real value of x

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed
solution very  quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
Askiitians Experts

Think You Can Provide A Better Answer ?