x6 - 10x3 + 27:

Dear ajinkya

x⁶ - 10x3 + 27=0

let x³ =t

so t² -10t +27 =0

discrimnent of this equation is negative so  no real value of t

so this equation has no real value of x

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed
solution very  quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin