Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Dear ajinkya
x3 + 149x2 - 50545x - 50693 = 0
in cubic equation you always try to find one root by insection.
here in this case x=-1 is its root
so (x+1) is its one factor
now devide the equation by (x+1)
s0
x3 + 149x2 - 50545x - 50693=0
(x+1) ( x2 +148x -50693) =0
now solve
x2 +148x -50693 =0
x = { -148 ±√1482 + 4* 50693} /2
x = 163 and - 311
so final solution is
x = -1, 163, - 311
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards, Askiitians Experts Badiuddin
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !