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Dear ajinkya
tanB = AD/BD = 24/BD
tanB/2 = r1/(BD-r1)
tanB = 2tanB/2 /( 1 - tan2B/2)
24/BD = 2 {r1/(BD-r1)}/ 1- { r1/(BD-r1)}2
BD = (24r1 -r12 )/(12-r1)
r1 =3
BD = 7
similerly
CD = 18
BC = 7+18 = 25
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