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Eight letters are to be kept in 8 envelopes. Find probability that at least one letter is kept in right envelope?

Pratik Sharma , 15 Years ago
Grade 12
anser 3 Answers
Badiuddin askIITians.ismu Expert

Last Activity: 15 Years ago

dear pratik

number of ways  of at least one letter is kept in right envelope(n)

              n= total ways - number of ways when all letter kept in wrong envelope

              n  =8!          -               8![1-1/1! +1/2! -1/3! .........+1/8!]

              

So probability =n/8!

 

calculate value of n and put here


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Pratik Sharma

Last Activity: 15 Years ago

Thats good, but i cant understand how the "number of ways when all letter kept in wrong envelope " came as " 8![1-1/1! +1/2! -1/3! .........+1/8!] " . 

Badiuddin askIITians.ismu Expert

Last Activity: 15 Years ago

Dear pratik

this is theorem proof is not in IIT JEE syllabus

If n letter are to be kept in n envelope such that no letter kept in  right envelope so number of ways=

   n![1-1/1!+ 1/2! -1/3! +..........(-1)n 1/n!)]

Regards

Badiuddin

 

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