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Grade:11

3 Answers

Amit Saxena
35 Points
8 years ago

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rishabh
27 Points
8 years ago

for a function to be continous left hand limit must be equal to right hand limit 

  lim ( sin2x) =    lim (ax=b)  =             by this we got =>(root 3)/2 = a(pi/6) +b

x->pi/6-            x->pi/6+

  similarly for f''

  lim (2cos2x) =  lim (a)   =                  by this we get a=1

x->pi/6-            x->pi/6+

 

hence b= (c) 

 

 

 

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Hanumant Gusain
39 Points
8 years ago

answer will c by just solving it by limit on rhl and lhl

then same for f'' from where you get value of a=1 and from f you will get    aΠ/6+b=(3^1/2)/2

and then equate

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