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for a function to be continous left hand limit must be equal to right hand limit
lim ( sin2x) = lim (ax=b) = by this we got =>(root 3)/2 = a(pi/6) +b
x->pi/6- x->pi/6+
similarly for f''
lim (2cos2x) = lim (a) = by this we get a=1
hence b= (c)
if liked then pls approve the answer by clicking yes below
answer will c by just solving it by limit on rhl and lhl
then same for f'' from where you get value of a=1 and from f you will get aΠ/6+b=(3^1/2)/2
and then equate
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