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Let a+b+c+ab+bc+ca+abc = 1000
Then The Possible Value Of a+b+c Is
A) 28
B) 36
C) 39
D) 42
hi prakhar
the expression is (a+1)(b+1)(c+1) - 1 = 1000
(a+1)(b+1)(c+1)=1001 = 7*11*13
from here we can conclude a = 6, b= 10 , c= 12
can be the possible values
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