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FIND THE SUM OF ALL NUMBERS GREATER THAN 10,000 FORMED BY USING THE DIGITS 0,2,4,6,8 NO DIGIT BEING REPEATED IN ANY NUMBER. Badiuddin askIITians.ismu Expert
148 Points
12 years ago

Dear shaurya

Let 2 at first position

rest 4 position can be filled by 4*4*4*4=256 ways

every digit from 0,4,6,8 come at unit place 256/4 =64 times

so some of all the digit at unit place = 64*(0+4+6+8)

each of 0,4,5,8 digit also occur at 64 times 10th hundred and thousand place

so sum of digit =64(0+4+6+8)(1+10+100+1000)   + 2 * 10000

similarly for the other digit

4 at first place sum =64(0+2+6+8)(1+10+100+1000)   + 4 * 10000

6 at first place sum =64(0+2+4+8)(1+10+100+1000)   + 6 * 10000

8 at first place sum =64(0+2+6+4)(1+10+100+1000)   + 8 * 10000

so total sum  =64(2+6+4+8)*3*(1+10+100+1000)   + (2+4+6+8) * 10000

solve it this will be your final result

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