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FIND THE SUM OF ALL NUMBERS GREATER THAN 10,000 FORMED BY USING THE DIGITS 0,2,4,6,8 NO DIGIT BEING REPEATED IN ANY NUMBER.
Dear shaurya
Let 2 at first position
rest 4 position can be filled by 4*4*4*4=256 ways
every digit from 0,4,6,8 come at unit place 256/4 =64 times
so some of all the digit at unit place = 64*(0+4+6+8)
each of 0,4,5,8 digit also occur at 64 times 10th hundred and thousand place
so sum of digit =64(0+4+6+8)(1+10+100+1000) + 2 * 10000
similarly for the other digit
4 at first place sum =64(0+2+6+8)(1+10+100+1000) + 4 * 10000
6 at first place sum =64(0+2+4+8)(1+10+100+1000) + 6 * 10000
8 at first place sum =64(0+2+6+4)(1+10+100+1000) + 8 * 10000
so total sum =64(2+6+4+8)*3*(1+10+100+1000) + (2+4+6+8) * 10000
solve it this will be your final result
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