#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# FIND THE SUM OF ALL NUMBERS GREATER THAN 10,000 FORMED BY USING THE DIGITS 0,2,4,6,8 NO DIGIT BEING REPEATED IN ANY NUMBER.

## 1 Answers Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear shaurya

Let 2 at first position

rest 4 position can be filled by 4*4*4*4=256 ways

every digit from 0,4,6,8 come at unit place 256/4 =64 times

so some of all the digit at unit place = 64*(0+4+6+8)

each of 0,4,5,8 digit also occur at 64 times 10th hundred and thousand place

so sum of digit =64(0+4+6+8)(1+10+100+1000)   + 2 * 10000

similarly for the other digit

4 at first place sum =64(0+2+6+8)(1+10+100+1000)   + 4 * 10000

6 at first place sum =64(0+2+4+8)(1+10+100+1000)   + 6 * 10000

8 at first place sum =64(0+2+6+4)(1+10+100+1000)   + 8 * 10000

so total sum  =64(2+6+4+8)*3*(1+10+100+1000)   + (2+4+6+8) * 10000

solve it this will be your final result

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

All the best.

Regards,
Askiitians Experts
Badiuddin

## ASK QUESTION

Get your questions answered by the expert for free